23)
Molar mass of Ca(NO3)2,
MM = 1*MM(Ca) + 2*MM(N) + 6*MM(O)
= 1*40.08 + 2*14.01 + 6*16.0
= 164.1 g/mol
use:
mass of Ca(NO3)2,
m = number of mol * molar mass
= 0.65 mol * 1.641*10^2 g/mol
= 107 g
Answer: 107 g
24)
Molar mass of NaHCO3,
MM = 1*MM(Na) + 1*MM(H) + 1*MM(C) + 3*MM(O)
= 1*22.99 + 1*1.008 + 1*12.01 + 3*16.0
= 84.008 g/mol
mass(NaHCO3)= 2.00 g
use:
number of mol of NaHCO3,
n = mass of NaHCO3/molar mass of NaHCO3
=(2 g)/(84.01 g/mol)
= 2.38*10^-2 mol
Answer: A
25)
Molar mass of SO2,
MM = 1*MM(S) + 2*MM(O)
= 1*32.07 + 2*16.0
= 64.07 g/mol
use:
mass of SO2,
m = number of mol * molar mass
= 2.65 mol * 64.07 g/mol
= 170*10^2 g
Answer: D
please provide explanation 23) How much CNO3)2 should be weighed out to have 0.650 A) 66.4 g B) 9768 C) 107 g D) 13...