Question

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NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier study, the population proportion was estimated to be 0.36. How large a sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04? Round your answer up to the next ger. Answer(How to Enter) 2 Points Keypad Hawkes Learning

Answer 1

Solution Given orig that the  = 0:36 E=0.04 . level 12' is. At 851. confidence 2=16857 21-0.85 2= 0.15 212 = 0.1512 = 0.075. 12212=20.075 = 1.44 1 Sample size (n) = (2212 1² x Ê ( 18) x 0.36 (-0.36) 11:44 0:04 299 (rounded to next integer) Sample size kn) = 2gg

solution Given that u= 40.5 o= 4.3 E = 0.19 12' is At son) confidence level 2- |- 80-). d - 0.80 a 0.20 1/2 - 0.20/2 = 0.10 2012 - 20.10 = 1.28 | Sample size an) = (22/2 x 6 11-28 X 4.3 0.1g Sample size (n) = 841