A bead with a hole through it slides on a wire track. The wire is threaded through the hole in the bead, and the bead...

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Answer 1

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Answer #1

A)

By Conservation of energy

mgh =(1/2)mV²+mg(2R)

mg(3.2R) =(1/2)mV²+mg(2R)

1.2gR =(1/2)V²

V2.4g

b)

Normal force at point A

N=mV²/R -mg =m[2.4gR/R -g] =m[1.4g] =(5.5*10^-3)(1.4*10)

N=0.077 N

Direction is downwards

Answer 2

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