Question

This basic problem demonstrates the while-loop. (USE MATLAB)

Write a Matlab function called steps that takes one scalar as an input argument and returns two scalars as output arguments. If it is called this way [n, d_left] = steps(d), then it sets n equal to the minimum number of steps required to move from a distance of one foot away from a wall to a distance less than d feet from the wall. The first step is 1/2 foot. If a second step is required, it is 1/4 foot. If a third step is required, it is 1/8 foot, and so forth, with each subsequent step being half the distance of the step before. The second output, d_left, is the distance to the wall after n steps. Here is an example run:

>>[n,d_left] = steps(0.001)

n =

10

d_left =

9.7656e-04

Your Function 1 function [n,d_left] = steps(d) ----input-error check- %--- if 1 error('Distance must be less than 1 foot.') end :- outputs -------- no steps have been taken, so n is and the remaining distance is 1 foot. d left 1; : ne % - 10 ---- SYOUR CODE HERE Use a while- loop to keep taking steps so long as the reminaing distance is greater than or equal to the input distance. 11 12 13 14 15 end 1я Code to call your function 1 n,d_left] steps (0.001)

Answer 1

MATLAB CODE------------------------------


function [n,d_left]=steps(d) 
% Error check
if(d>=1) 
error('distance must be less than 1 feet') 
end

%initiate output
n=0;
d_left=1;
dnew=1;
while(dnew>d) 
dnew=dnew/2;
n=n+1;
end
d_left=abs(d-dnew*2) 
end

OUTPUT------------

steps(0.001)
d_left =    9.5312e-04
ans =  10