Question

F) 3w-5 w-25 (2) Which of the following definite integrals cannot be evaluated using the Fundamental Theorem of Calculus? (This has nothing to do with being able to find an antiderivative), D) S B) sin() In(x) dx (C) x tan(x) dx A) dr dx 1+e In(x2 +1) dx sin(® dx\ (G) J V+ sin H) F) 2 dx o )u xb [(x)1-(x)ul, 3 x+1dx be evaluated using the FTOC ? C)

Answer 1

dx Su ieton dx utz ut du- xt2'dx af al Jutt-4ui Qd 4u-44 4 Jut2- 4 (t (.% Qe2 t 1 2 (3x Bu2) 15

Actordih to tondono etel - fCb)-fla) foudn 3 dit3-0431 IS dSe C3 +04 PF43 6 9 S3d -fudu u du= duSinndn nC intd( noy LCoy-e) dk 9ncx) Cos u T(n -9nlr) Cesn Iner Cast ilx)

9nca) Cost Cil Anc3) t 9)t n1). Cos 1)+91 -Ci(vt Gis) n(a) Ces Ca dve fondom ite! be ofue Cantal w TRoosim tan w dr y nelmeta findamstel T' i a hon ptgrd tcannot TRonm be dral ( dn du 7 au: C2 C6-2 The intd hecamu du dy

da -- du- 2 du dv L du 아랑 flu)-e du V hare lose torm oloes not V Peaall U=J Elu)=e -3 et -t 6ITC e eEletce E(12) eEle)+C e GC12)

3nd forala mtel fRayr n ig not possible f n tondion (31n bccs 2 of 1+ Sinn adx byfindomda This is also Cannat Ae salve thPoMm (H) Qn Cn241) dn Wrute it as ve Car 1Oncx) d n parts- 1 1 Onc Carlyy -ate tan J+ 9ncr) す-2n2 -) - 241 + f1dn

drc tan C) 2 -arctan(ut on (x41 So r/ x encxt1)-a(-arc tan x) C M anlot1)- 2-arc Ctantc/ 2 J On (-1 -3 (- are (tan)te o-nc2)-9-1) 4 -2tgn 2