Question

1 Zno Zn2+ con +2 é "Cu 2+ hog) + 2 é Cuica) Znas + Cut 2 hout Cus FE 0.34 F. E: -0.76 21 2nw + Zn Zon + 2 é TF + 26 Few Znow & Fell Zarag, "Fels) E": - Full 3) Few Fearot 20 the Luc Few + 20249) ► Fehling) * Cu E = 0.45 v E: 0.34 Elan I

Answer 1

Eose Anodes -Ear (Cathod Red Eccer - Ered Cathodes- Ered (Anode) = Een Een osa 1 log (P12 - number of es in reaction E2/22+ Cosi.) = .0.70 (given) Early = 0.340 Ecell = 0.76+ 0.34 = -0.42 concentration are not given, so taking unit Ecell - Ecer- dostal doge 1 Ecent Ecell = -0.42 Ecell - Eily = – 0.76 + 60.45) - - 1.210 Ecey - Elly = 0.45 + 0.34 = 0 T9v Answers are according to given date but these datore not correct data according to Rot Electochemical series. (3) Ecell = Ecell =