Question

From DESIGN WITH OPERATIONAL AMPLIFIERS AND ANALOG INTEGRATED CIRCUITS - Sergio Franco - Third Edition

EXAMPLE 3.19. Design a biquad filter with fo = 8 kHz, BW = 200 Hz, and a 20-dB resonance gain. What is the value of HoLp? Solution. Let Ci 3D С; 3D I nF. Then, Ra 3D Rs - 1/(2л х 8 х 10° х 10-%) %3D 19.89 kR (use 20.0 ks2, 1%): Q — 8х 10°/200%3 40; Rz 3D 40 x 19.89 3 795.8 kR (use 787 ks2, 1%); Ri = Rz/1020/20= 78.7 k2, 1%; HoLp = 20.0/78.7 = Q.254 V/V or 11.9 dB

Repeat the problem writing the equations necessary to reach given solution.

Answer 1

Snample 3-19 have R R4R5 Fos C=C = C = t nF ard we R= Ry= Rs = => Rc R= X fa% tolederce R ZO K Use - 200 R2 40x 19 87 kn = T95-8 kn = R2 : f0 1% tolerence R2 787 Kn Use (o20 lo 20 dB R2 Goin = 20/20 187Kn T8.7 K RI 20 Kn O-254 vlv HoLP Co2olog (0.25) -l.9 dB