Question 1 (1 point) Nitrite ion isha weak base in aqueous solution; Kb is equal to 2.2 x 10-11. Calculate pKfor th...

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Answer 1

Answer #1

For a given conjugate acid -base pair Ka*Kb = Kw where Kw is ionic product of water = 1.0*10^-14 M²

Given that Kb of nitrite ion = 2.2*10^-11

Ka = Kw / Kb = 1.0*10^-14/(2.2*10^-11) = 0.00045454545 = 4.6*10^-4

But, pKa = -log(ka) = -log(4.6*10^-4) = 3.34 $\approx$ 3.3

pKa of the nitrous acid(HNO2) is 3.3

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