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Compound G: Molecular formula = C9H12. Key Infrared signal: 3082, 749, 699 cm 5H, m 3H, t 2H, sextet 2H, t 10 Heoe-ese Pprn DCompound K: Molecular formula = C4H8O2: IR signal: 1743, 1087 cm H, singlet 3H, t quartet 3.5 1.0 PPN Draw your final in thisCompound E: Molecular formula = C4H10O. Key infrared signals: 3342, 1099 cm E 6H The signal at 3.8 ppm disappears with the ad

Please give the structure based on the NMR spectra depicted.

Compound G: Molecular formula = C9H12. Key Infrared signal: 3082, 749, 699 cm 5H, m 3H, t 2H, sextet 2H, t 10 Heoe-ese Pprn Draw your final in this box. Compound H: Molecular formula C$H10O. Infrared signal: 2874, 2719, 1726 cm 3H, t 9-10 2H, 2H, t udd sextet 1H, singlet 2H, pentet 1.5 2.0 1.0 PPM 3.0 t0 5 10.0 9 9.0 8.5 8.0 7.5 7.0 6.5 PPM Draw your final in this box. 4
Compound K: Molecular formula = C4H8O2: IR signal: 1743, 1087 cm H, singlet 3H, t quartet 3.5 1.0 PPN Draw your final in this box.
Compound E: Molecular formula = C4H10O. Key infrared signals: 3342, 1099 cm E 6H The signal at 3.8 ppm disappears with the addition of D2O. 1H 1H 2H 4.0 3.0 2,5 2.0 1.5 1.0 PPM 0.5 Draw your final in this box. HC O
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Answer #1

from the given H1 NMR spectrum we identify structure based on multiplicity followed by n+1 rule n is number of hydrogens on adjacent carbon if n=0 multiplicity is singlet if n=1 doublet n=2 triplet like (-Hо н (4нE) сH, —сH сH, С2# Sextt} SH Aro Matc Mulipkt о9 ppmy 3 gripht -chg Avomaie 6 PpM 2LH Sexrt —СH, -фрym со c-с 4,6q(4 диt) не сH- сHg (зи sthngel) Сзнint) зHgriplet -cny - 2-3PPM 3-7Pp 3Hsiugluf сHg ra \743 -о -с tao toyа CHIOO TIgnep. HT с

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