In any peptide two side is present, one is N terminal i.e. free NH2 group is present and another is C terminal where free COOH group is present. When more than one amino acid is join then it's called peptide . The most stable form of amino acid is zwitter ionic form where it's in neutral form. With variation of pH they present in different form . Similarly, here in heptapeptide the dicationic form is only possible when the two free NH2 group is in protonated condition . So, it's only possible at low pH here is given pH 3 . As, at high pH COOH becomes deprotonated and anionic form is observed. Hence, the answer.
Which of the pH conditions shown below would give this heptapeptide an overall charge of +2? COOH CH2 CH NH NH. CH5 HN...
Consider the following molecules: b. а. CHS CH3 O NH— CH—CH2—ОН NH2-CH-C-OH CHз d. C. CHз о Но-СН—С—ОН НО—С—С—С—ОН CH3 [Select ] i. Which of the molecules above is a secondary amine? ii. Which of the molecules above will be a zwitterion under physiological conditions (pH 7)? (Select) [Select ] ii. Which of the molecules above has two acidic protons?