Question 4 . 1 pts Which sample will require less heat to undergo a temperature change of 15°C; 10 g of aluminum or...
A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C. If the specific heat of aluminum is 0.900 J/g- °C, what is the mass, in grams, of the sample?
4. Calculate the heat change in a system (q) when 12.0 g of water is heated from 20.0 °C to 100.0 °C. 5. A 295 g aluminum engine at an initial temperature of 3.00 °C absorbs 85.0 kJ of heat. What is the final temperature of the engine? The specific heat capacity for aluminum is 0.900 J/(g K).
Question 4 of 8 > Substance lead Specific heat capacity (J/g °C) 0.128 0.235 0.385 silver copper iron 0.449 aluminum 0.903 4.184 water An unknown substance has a mass of 18.9 g. The temperature of the substance increases by 18.3 °C when 81.3 J of heat is added to the substance. What is the most likely identity of the substance? O aluminum silver O water O copper
How much heat is required to raise a 5.38 g sample of aluminum (26.98 g/mol) from 29.0°C to a temperature of 894°C? The information below may be useful. Specific heat capacity of Al (solid) = 0.903 J/g x *C Specific heat capacity of Al (liquid) = 1.18 J/g x *C ΔHfusion = 10.7 kJ/mol Melting Point of Al = 660*C
The temperature of an object increases by 48.3 °C when it absorbs 3701 J of heat. Calculate the heat capacity of the object. C = 0.240 The mass of the object is 319 g. Use the table of specific heat values to identify the composition of the object. Substance gold silver Specific heat (J/(g · °C)) 0.129 0.240 0.444 0.900 iron aluminum
< Question 7 of 19 > The temperature of a sample of aluminum increased by (23.3- \text{°C}\) when (269\text{J}W) of heat was applied What is the mass of the sample? Substance lead silver Specific heat J/g. °C) 0.128 0.235 0.385 0.449 0.903 copper iron aluminum Vm=10) W\text{g} \0
Question 9 of15 The temperature of an object increases by 41.6 °C when it absorbs 3641 J of heat. Calculate the heat capacity of the object. The mass of the object is 365 g. Use the table of specific heat values to identify the composition of the object Substance Specific heat (J/(g . ! gold silver iron aluminum 0.129 0.240 0.444 0.900
A 3.00-g sample of aluminum pellets (specific heat capacity=0.89 J/°C g) and a 18.50-g sample of iron pellets (specific heat capacity = 0.45 J/°C-g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 77.4 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Final temperature = 20.23 °C An error has been detected in your answer. Check for typos. miscalculations...
Specific heat J/(g·℃) The temperature of a sample of copper increased by 24.0 °C Substance when 255 J of heat was applied. SubstanceSpecific heat J/(g·℃)lead0.128silver0.235copper0.385iron0.449aluminum0.903What is the mass of the sample? m = _______ g
A 3.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 11.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C·g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 73.8 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Please be super specific on how you get to each step!