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How many grams of Na2EDTA.2H2O (FM 372.23) should be mixed with 1.95g of Ca(NO3)2.2H2O(FM 201.12) in a 500-mL volumetri...

How many grams of Na2EDTA.2H2O (FM
372.23) should be mixed with 1.95g of
Ca(NO3)2.2H2O(FM 201.12) in a 500-mL
volumetric flask to give a buffer with pCa2+= 9.00 at pH 9:00? [ αY4- = 0.041 at pH 9; log Kf = 10.65 at 25degree C
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Answer #1

logK = 10.65 So K = 4.47 x 1010 Formation constant of Ca(EDTA)]-2 = 4.47 x 1010 At pH =9, the fraction of EDTA that exists Y-

Let n be the number of moles of EDTA to be added. mmols of Ca+2 = 1.95 g/(201.12 g/mol) = 0.009696 mol pCa+2 = 9.00 That is (

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