Solution:
(a) The cost function of MBI is C1(y1) = y12
Cost function of Pears is C2(y2) = 5y2
aggregate demand = y1+y2 = y =106 - 105p
Therefore inverse demand function is:
p = 10 - y/105
MBI is the leader and Pears is the follower firm
Profit function of Pears firm is
Profit2 = P*y2 - C2
= (10 - (y1+y2)/105)*y2 - 5y2
By derivating profit function w.r.t to y2, we get
= 10- (y1+2y2)/105 - 5 = 0
y2 = (5*105 -y1)/2
Profit function of MBI
Profit 1 = P*y1 - C1
(10 - (y1+y2)/105)*y1 - y12
Substituting value of y2 in y1
(10-((5*105 -y1)/2 )+y1) /105)*y1 - y12
=(10- (5*105 +y1) /2*105)*y1 - y12
Derivating above equation w.r.t to y1
(10 - (5*105 + 2y1) /2*105) - 2y1=0
2y1 * 2*105 +2y1 = 10-5*105
y1 = (10-5*105 )/(4*105 + 2)
substituting value of y1 in y2
y2 = (5*105 -y1)/2
y2 =( 20*1010 + 106 - (10-5*105 ) ) / (4*105 + 2)
Substituing value of y1 and y2 in p
p = 10 - (y1+y2)/105
p = 10 - (((10-5*105 )/(4*105 + 2))+(( 20*1010 + 106 - (10-5*105 ) ) / (4*105 + 2)))/105
= 10- (2*1011 + 106)/105 (4*105 + 2)
(B) Cournot equilibrium
Profit function of Pears firm is
Profit2 = P*y2 - C2
= (10 - (y1+y2)/105)*y2 - 5y2
By derivating profit function w.r.t to y2, we get
= 10- (y1+2y2)/105 - 5 = 0
y2 = (5*105 -y1)/2 (BR eqution of firm 2)------------------------(1)
Profit function of MBI
Profit 1 = P*y1 - C1
= (10 - (y1+y2)/105)*y1 - y12
Derivating it w.r.t to y1, we get
10 - (2y1+y2)/105 - 2y1 =0
substituting value of y2 in the above equation we get
= 10 - 3y1/2*105 - 5/2 -2y1 =0
15/2 = (3+4*105) *y1 / 2*105
15*105 = (3+4*105) *y1
y1 = 15*105 / (3+4*105)
Substituting value of y1 in y2
y2 = (5*105 -y1)/2
= (5*105 -(15*105 / (3+4*105)))/2
=(15*105+20*1010 - 15*105)/ 2*(3+4*105)
y2 = 1011 / (3+4*105)
Therefore p = 10 - (y1+y2)/ 105
p = 10 - ((15*105 / (3+4*105))+(1011 / (3+4*105))/105
p= 10 - (15*105 + 1011) / 105*(3+4*105)
Price in cournot model is more than stakalberg model
5.* MBI and Pear are the only two producers of computers. MBI started producing earlier than Pear. MBI's costs of p...
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