Assuming pressure to be constant Volume is directly proportional to its absolute temperature
Hence V1/T1=V2/T2
V1 = 2L ; T1 = 26 + 273 = 299 K
T2 = Temperature of liquid nitrogen = -196 + 273 = 77 K
All temperatures must be in kelvin
2/299=V2 / 77
V2=2/299 x 77
=0.52 litres
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