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Uranyl nitrate decomposes according to UO2(NO3)2(aq) -> UO3(s) +2 NO 2 (g)+ 1/2 O2(g) The following data were recorded for th

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Answer:

Given reaction is

UO2(NO3)2(aq) -----> UO3(s) + 2NO2(g) + 1/2O2(g)

Zero-order rate law is

[UO2(NO3)2]=-kt+[UO2(NO3)2]0 and the plot of [UO2(NO3)2] vs t gives a straight line with slope=-k.

The first-order rate law is

ln[UO2(NO3)2]=-kt+ln[UO2(NO3)2]0 and the plot of ln[UO2(NO3)2] vs t gives a straight line with slope=-k.

The second-order rate law is

1/[UO2(NO3)2]=kt+1/[UO2(NO3)2]0 and the plot of 1/[UO2(NO3)2] vs t gives a straight line with slope=k.

Where k=rate constant, [UO2(NO3)2]0=Initial concentration at t=0 min

[UO2(NO3)2]=concentration of UO2(NO3)2 at time t.

The calculated values are tabulated below

Time(s) [UO2(NO3)2] (M) ln[UO2(NO3)2] 1/[UO2(NO3)2]
0 1.41E-02 -4.259455082 70.77140835
20 1.10E-02 -4.513502997 91.24087591
60 7.58E-03 -4.882242079 131.9261214
180 3.02E-03 -5.802498448 331.1258278
360 5.50E-04 -7.50559228 1818.181818

[UO2(NO3)2] vs t plot is

0.016 0.014 y = a + b^x No Weighting 1.76722E-5 Equation Weight Residual Sum of Squares Pearsons r. Adj. R-Square 0.012 -0.9

ln[UO2(NO3)2] vs t plot is

y = a + b*x No Weighting 0.01399 o Equation Weight Residual Sum of Squares Pearsons r Adj. R-Square -0.99899 0.99732 o Inter1/[UO2(NO3)2] vs t plot is

2000 1800 - Equation y = a + b*x Weight No Weighting Residual Sum 264186.0743 of Squares Pearsons r. 0.93952 Adj. R-Squar 0.

From the above plots, the plot of ln[UO2(NO3)2] vs t gives a straight line with R2=0.997.

Therefore the order of the reaction is first order.

The slope of the line=-k=-0.00882 min-1

Therefore rate constant, k=0.00882 min-1.

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