Question

Using the Larson-Miller data shown below, predict what would be approximately the maximum allowable stress at 800 °C to have

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Ans:

T = 800 deg C = 800 + 273 = 1073 K

Rupture time = 15000 hr

Hence Larsen miller parameter can be calculated as follows:

T*(C + log(tr)) = 1073*(20+log(15000)) = 1073*24.176 = 25.94*103

From the graph setting x-value to 25.94 we get (y-value) stress of 70 MPa approx.

Hence maximum allowable stress is 70 MPa.

Add a comment
Know the answer?
Add Answer to:
Using the Larson-Miller data shown below, predict what would be approximately the maximum allowable stress at 800 °C to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Animated Figure 9.41 shows a plot of the logarithm stress versus the Larson-Miller parameter for an...

    Animated Figure 9.41 shows a plot of the logarithm stress versus the Larson-Miller parameter for an S-590 alloy. A component made of this alloy must have a creep rupture lifetime of at least 20 days at 750°C (1023 K). Compute the maximum allowable stress level in MPa. Larson-Miller parameter 12- 103 (R-h) 103 T(20 + log ir)("R-h) Larson-Miller parameter 2.2- 10s (K-h) Stress 6.9 MPA Stress 1 105 psi 25 30 35 4045 50 1000 100 100 CD 10 9...

  • Chapter 08, Problem 8.05 amated Eigurea4 shows a plt of the lagarithm stress versus the Larson-Miller...

    Chapter 08, Problem 8.05 amated Eigurea4 shows a plt of the lagarithm stress versus the Larson-Miller parameter for an S590 alcy. A cormponent made of this alloy must have a creep rupture lfetime of at least 20 days at 750c (1023 maximum allawable stress level. MPa me tolerance is 4- 10%. Click if you would like to Show Work for this question: Open Shaw Wark Larson-Miller parameter 12-103 (R-h) Larson-Miller parameter 2.2 103 (K-h) Stress = 6.9 MPA Stress =...

  • T(20 + log t)('R-h) 25 30 35 40 45 50 * x103 x103 x103 x103 x103...

    T(20 + log t)('R-h) 25 30 35 40 45 50 * x103 x103 x103 x103 x103 x103 Larson-Miller parameter = 12. 103 (R-h) 100,000 Larson-Miller parameter = 2.2. 103 (K-h) Stress = 6.9 MPA Stress = 1 . 103 psi TITUTI 100 Stress (MPa) 10,000 Stress (psi) IIIIIIITTI 10 16 1000 20 24 1 28 28 16 xlo3X103 X103 X103 X103 T(20 + log t)(K-h) * Your answer is incorrect. For an 18-8 Mo stainless steel (Animated Figure 8.36), predict...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT