Question

Need 6.6 solved

6.2 Using Gauss elimination and back substitution, solve 8 2 3 1 4 6 2 4 X2 3 4 14 2 6.6 Solve Problem 6.2 using the Jacobi iterative method. Start with x(0) x2(0) x(0)0, and continue until (6.2.2) is satisfied with e 0.01 _ -

Answer 1

6.R) Given 2 4 4 4 g 2 1 2 4 6 2 2 R22R-R R SRs3RI 2 22 26 109 R3 IDRe- 26 R 2. 13 ID35 1012-60 -GO Now 10) 233 = -60 0.0592 l012 10n2t323=5 5.1776 0.51年子 82 ナ272 +22 ニ3 2.0338 221 0-259 0 er D.5177 a 259 9, 2 O

6.6) Given ,te) ,l0) = 22 (0) 0. and tom, Given matii is piagonally Dominot 8a1 t 222 +23-3 42, + 62, 223 4 371 42 +142s 3 292-23 Now 4-223-411 2 2 412 32 1-1 K 14 .3-29,-23 4-293 421 Iterations 23:2-492-3 )=0.37S O. 666 o-1428 O.1907 o.369 O.1277 2 . 298 0.582 -0.00328 4 O. 229 0.0S72 On 543 O.268 -0-0402 0.0694 -0-5010 0 244 0c0525 O524 O512 A O.063-2 0299=2y