Question

Question is asking to solve for the Fky and Fkx forces.

12. Calculate the horizontal and verticaljoint reaction forces at the knee of an 85 kg individual landing unilaterally from a 45 cm platform, given the free-body diagram of the shank below: (15 pts.) 350 N F Fky = F 600 N = ay =230 N Fkx quadriceps 64° 0.0435 quadriceps Shank mass/body mass = 20 m/s 730 F F kw 5.3 m mg Fay Fax a= -1500 rad/s2

Answer 1

Take the components of fquadriceps along x and y directions.

Write equation of force in both directions solve itthank you for reading. Keep solving these types of questions

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