Question

Bardi Trucking Co., located in Cleveland, Ohio, makes deliveries in the Great Lakes region, the Southeast, and the North...

Bardi Trucking Co., located in Cleveland, Ohio, makes deliveries in the Great Lakes region, the Southeast, and the Northeast. Jim Bardi, the president, is studying the relationship between the distance a shipment must travel and the length of time, in days, it takes the shipment to arrive at its destination. To investigate, Mr. Bardi selected a random sample of 20 shipments made last month. Shipping distance is the independent variable and shipping time is the dependent variable. The results are as follows:

#   Shipment Distance Miles Shipment time (days)
1 626 5
2 801 11
3 733 4
4 640 3
5 756 13
6 790 8
7 718 8
8 652 3
9 792 12
10 629 4
11 696 9
12 718 10
13 754 3
14 648 4
15 666 3
16 831 10
17 691 13
18 822 9
19 793 3
20 784 11

Show your work and explain:

1.- Fill in the blanks. (Round your answers to 3 decimal places. Negative values should be indicated by a minus sign.)


y ________
x̄ ________
sx _______

sy _______

r ________

2. State the decision rule for 0.01 significance level: H0: ρ ≤ 0; H1: ρ > 0. (Round your answer to 3 decimal places.)

Reject H0 if t > _______

3. Compute the value of the test statistic. (Negative value should be indicated by a minus sign. Round your answer to 3 decimal places.)

Value of the test statistic __________

4. Can we conclude that there is a positive correlation between distance and time? Use the 0.01 significance level.

_________H0. We_________ conclude that there is a positive correlation between distance and time.

5. Coefficient of determination __________

6. _______ % of the variation in shipping time is explained by shipping distance.

7. Standard error ________

8. Would you recommend using the regression equation to predict shipping time? No Yes

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Answer #1

EXCEL (Data Analysis) output:SUMMARY OUTPUT Regression Statistics Multiple R 0.518088261 R Square 0.268415446 Adjusted R Square 0.22777186 Standard Errorj=7.3 i = 727 = 68.095 s, = 3.743 r=0.518 (2) Reject H, ift> 2.552.(0.518) V20-2 V1-0.5182 2.1977 0.8554 = 2.569 Value of the test statistic: t = 2.569. Reject H. We can conclude that there isStandard error: SE = 3.289 No.

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