Question

(4.2) Consider the integral -f 1 J dec 1+3 (a) Show that (4) 1 da 1 +x3 dr 1+r3 (b) Deduce that (3) -re) J f() dr where f is

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Answer #1

SOLUTION- (A)

1 da 13 J =

Consider 1 da 13 I =

Substituting dy y2 dr so that

1 1 dy y2 I = 1 X

Which is dy 1+y I =

So that 1 dx da 1

SOLUTION-(C)

Note that 1 dx 1 3 1 da 1+3 1 da 1 0

Which is 1r da 1 +3 1 dr 1 3 1 dr 1+3 da 1 r _ 0

That is, 1 da J .2 1 so f (x) 1 r2 is the function

Using Gaussian quadrature, we have (b- a) (b- a) (b a) (b- (b+ a) (ba) (b+ a) a ) c2f cof 0T )cif( + + + 2 2 2 2 2 2 is the approximate integral which equals 1.20987654321

SOLUTION-(D)

The result is not exact because f (x) 1 r2 is not a polynomial function of degree 2 or less

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(4.2) Consider the integral -f 1 J dec 1+3 (a) Show that (4) 1 da 1 +x3 dr 1+r3 (b) Deduce that (3) -re) J f() dr wh...
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