Question

find the force in each member

.48SM 1.485m W-SkN/m F lo leN

Answer 1

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Given : S 4S F10KN AJ MA Step E NA a- Pomt A equini egustius Ar asti m Faces aSu F-10KN & UPL- SKN UDL IMt equwelewt Ayot canvD AMO Poin oad -lomk Poivt lo^ ^ DDL e UDL aCs elwey cemkyecl e mid Poiut Sx (4.04)KN 20.2-KN- CAS 2.2.m.

20 2-KN K-k do AJ MA APply Egn canvhiem haarantd cdicos in dichon towands niguiPo iHve. A oKN O A 16 kN uPrd Fdc, inyakoa direchon \C PGKv« A 20. 2KN -20 2KN EO AT ve MA G Cu(CIOCKuie Mowcuhabub A) ja po o(2.911.4) = 0 MA 10 MA = 42 KN 20 2KN MA = 43:90kN.u A, Stef 2 Le Assume yo cl1 dke Faces iw memlehs Le Tviuts c t tesile Fdces. as& tu Faice elnoy, ac

Canide Divt 4ue Mewi leu AG is FAE Letthe Fhu eckng A FAE o AE T A Ar MA FAE+ AT Ao AF-A 20 2kN 20.2KNC) Concde Tiut £ Fafe - ec- loKN=0 - Fee FecE10k FefFeFc Fef FeE Resolve te Fa) ces Fef Feo e FeE sin4 o KN

Canfide Toin 20- 2 K FDR FDC FPE:202Krí FDE FP FDC FDe-FPD* FDB- +KNFoo- Foc : 1kn FED FeD FRsos- FRE Gnr° at ivt (E FED FER FEA FED-FEA fEn s'muc FEC Sinr + Fec S4c FERSO4r Fec FED FEC= FERO

Step 3 : Tebulan Fw Nalime Membon S. NO \KN) C AE 20 2 20 2 2. ロE C D notum. o