Correct answer is : (E.) 3.7 g
Explanation
concentration KCl = 0.10 M
volume KCl solution = 0.500 L
moles KCl required = (concentration KCl) * (volume KCl solution in Liter)
moles KCl required = (0.10 M) * (0.500 L)
moles KCl required = 0.050 mol
mass KCl required = (moles KCl required) * (molar mass KCl)
mass KCl required = (0.050 mol) * (74.55 g/mol)
mass KCl required = 3.7 g
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