A =
Now we apply elementary row operations on A
Step I : (1/5)R1 = R1
Then A becomes =
Step II : R2-2R1=R2, R3+3R1=R3
Then A becomes =
Step III : R1+2R2=R1, R3+2R2=R3
Then A becomes =
Now, U = E1(5)E21(2)E31(-3)E12(-2)E32(-2)
i.e., U =
.
Question 14 [10 points] Given the following matrix A, find an invertible matrix U so that A is equal to UR, when R...
Solve for A: You can resize a matrix (when appropriate) by clicking and dragging the bottom right corner of the matrix -4-6-3 2 2 -6 -3 A1--1 6 -8 7 -7 -10 8 2 3 -5-4 000 A-0 0 0 O O 0
Solve for A: You can resize a matrix (when appropriate) by clicking and dragging the bottom right corner of the matrix -4-6-3 2 2 -6 -3 A1--1 6 -8 7 -7 -10 8 2 3 -5-4 000...
Solve the following system of linear equations: 3x1+6x2−9x3+6x4 = 6 −x1−2x2+8x3+3x4 = −17 2x1+4x2−3x3+7x4 = −4 If the system has no solution, demonstrate this by giving a row-echelon form of the augmented matrix for the system. You can resize a matrix (when appropriate) by clicking and dragging the bottom-right corner of the matrix.
Question 1 [10 points] Given the following matrices A and B, find an elementary matrix E such that B- EA You can resize a matrix (when appropriate) by clicking and dragging the bottom-right corner of the matrbx. 4 6-6 0 7 0 5-2 -4 -7 1-10 -4 6-6 0 4 -4 9-3 4 -4 9-3 o 0 0 E- 0 0 0
Help with system of linear equations.
Question 11 [10 points] Solve the following system of linear equations 2x1-4x2 2x3+4x46 2x1+5x2+x3-5x4 12 x1+3x2+x3-6x 11 -2x1+6x2-x3-2x4 -14 if the system has You can The system has no solution no solution, demonstrate this by giving a row-echelon form of the augmented matrix for the system. appropriate) by clicking and dragging the bottom-right corner of the matrix. Row-echelon form of augmented matrix: 0 0 0 Official Time: 16:52:07 SUBMIT AND MARK
Question 4 [10 points] If E, F, G are the following elementary matrices, compute the given matrix expression. You can resize a matrix (when appropriate) by clicking and dragging the bottom-right corner of the matrix. 1 0 0 0 0 1 0 0 1 000 0 1 0 0 E = F= 1 0 0 0 0 -5 0 0 0 0 1 0 0 0 0 1 G= 0 0 1 0 0001 0010 0 5 0 1 000...
Please show all steps in completing this problem, thank
you very much!
Solve the system Ax=b using the LU factorization of A and the matrix b given below. -2 0 0 1 -1 -2 7 A=LU= -2 -1 0 0 1 3 -17 2 -1 -2 0 0 1 -5 b= 12 12 -10 You can resize a matrix (when appropriate) by clicking and dragging the bottom-right corner of the matrix. The system has infinitely many solutions Number of Parameters:...
3. (Auqmented Matrices, Reduced Row BEchelon Form). In each of the following, the augmented matrix is in reduced row echelon form. In each case, find the solution set to the corresponding linear system. 1 0 010 1-10 0-5 11 0-9 o) o1 0 (ii). 01 -6 (008 1 -59 0| 2 0 1 0-7 17 0318 (iv)o o 1 9 -5 00 1-2 (v)0 00 0(vi). 1
In this exercise you will work with LU factorization of an matrix A. Theory: Any matrix A can be reduced to an echelon form by using only row replacement and row interchanging operations. Row interchanging is almost always necessary for a computer realization because it reduces the round off errors in calculations - this strategy in computer calculation is called partial pivoting, which refers to selecting for a pivot the largest by absolute value entry in a column. The MATLAB...
Question 3 [10 points] Consider the following matrix A and its reduced row-echelon form: A = [-3 3 6 12 0 151 | 1 -1 -2 -4 0 -5 -6 3 9 15 12 18 rret(A) |-1 -1 0 -2 8 -3 [1 0 -1 -1 -4 -1] 01 1 3 -4 4 0 0 0 0 0 0 0 0 0 0 0 0 Find the dimensions of row(A), null(A), and col(A), and give a basis for each of...
Given the matrix A and its reduced row echelon form R, answer the following questions. A= 10 20 3 4 1 1 60 7 6 11 6 1 10 10 2 1 8 2 16 18 R= 1 0 2 0 3 4 0 14 0 4 2 000134 000000 Find a basis for the column space of A and the row space of A. Basis for column space of A: with a comma-separated list of vectors enclosed with braces...