1.75 inch dia hole in a .75 inch plate of A36 steel. A force of 34000 lbs vertical to plane is applied to the hole. Use bearing stress to determine stress placed vertical to the plane and at 45 degrees to the plane
SOLUTION:
Projected area for bearing stress : A = 1.75*0.75 = 1.3125 in2
Stress in the vertical plane = Sv = P/A = 34000/1.3125
Sv = 25904.76 psi : ANSWER
Now Sv is the principal stress in vertical direction.
Now stress in the plane 45 degree to the vertical plane = S = (Sv/2) + (Sv/2) cos( 2*45)
S = 25904.76/2 = 12952.38 psi
S = 12952.38 psi : ANSWER
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1.75 inch dia hole in a .75 inch plate of A36 steel. A force of 34000 lbs vertical to plane is applied to the hole. Use...
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