Question

An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% C, 4.50% H, and 63.32% CI. Find the molecular formula for the compound.

Answer 1

- if we took 100g of compound 7 will have mass of c = 32-189 mass ob H = 4.50g mass ob cL = 63.32g ? u molas mass of molas mass or molas mass of c t cl = = = 12.0107 g/mol 1.00794 9 not 35.453 /mol mol = mass molasmass mols of c 1 - =2.68 molc . = 32.189 12.0107 stimol 4.50g " . = 1.067948/mo- mols of it - - 4.46 molt mols of CL - " 63.32g 35.453 91 mor = = 1.79 mol CL

1 for Relative comparison divide above mol values with least value O I 2 c = 2.68 mil . = 1.50 = R 1.79 mol H & 4.46 mol = 2.50 = 5 1:n a mot I= 1.29ml = 1 llame above we got fractional values, so multiply with least number 2 for make it whole number. : ca 3x2 = 3 1. HD Sexc=s a 3x2 = 2 . Empirical formula ;- Cat och

I molar mass of compound = 823.94 g/mol nolar mass of Empirical formula - Ratio ob .98 g/mol molecularits - Compound molas mass Empirical Melax mass 223 e 111.98 g/mol compound molector foro mula ;- C3x2H S x2 Clay 2 Cohio Clu .: Ansli molecular formula; Cothioclul Empirical formula :- Cats Ch₂