Question

xercise 14.16 thodynamic 2. The equilibrium constant for the following reaction is called the fluoride: constant for the foll

Help please! Show work

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Caf(s) - Ca2+ (aa) + 2F (aa) Kakop -3.2 X10-11 when an lonic solid is dissolved in liquid the aquacous part and solid part re27 increases Cafs) Cacaq) + 25 aa) Tincreases Backward direction when Nat will added to the solution it will dissociate intod) Ca fr (s) Cat can) + 2F antial (5) chang (25+0.2496) equilibriu Added at Kap = (s) (25 +0. 24962 3.2x10 11 = ( ) x (45² +

Add a comment
Know the answer?
Add Answer to:
Help please! Show work xercise 14.16 thodynamic 2. The equilibrium constant for the following reaction is called the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 2. The equilibrium constant for the following reaction is called the "solubility product" of calcium fluoride:...

    2. The equilibrium constant for the following reaction is called the "solubility product" of calcium fluoride: CaF2(s) - Cal(aq) + 2F-(ay) K = Kp = 3.2 x 10-11 (a) Write an expression for the equilibrium constant of this reaction in terms of concentrations. Why do you suppose we call this a solubility product instead of a solubility quotient or ratio? (b) Calculate the equilibrium concentrations of Ca2+ and F if excess solid CaF is placed in water. (c) in which...

  • APP-17 A 4 Problem Set 13 CHEM 1252 October 21, 2019 Textbook Reading Assignment: 14.6-10 Additional...

    APP-17 A 4 Problem Set 13 CHEM 1252 October 21, 2019 Textbook Reading Assignment: 14.6-10 Additional Practice Problems: 1466 -68.20.73.75.27.79.83.86-87,89,101,107,111-115,119 1. Ammonia and hydrogen sulfide can both be formed directly from their elements. At 90 "C... Nale) + 3H2(e) -2NH3G) * = 120 Hale) + SC) - H256) K = 0.068 Find Kat 90 °C for the following reaction 2NH3(e) + 35() - 3H.SG) + Nale) K? 2. The equilibrium constant for the following reaction is called the solubility product...

  • Learning Goal: To learn how to calculate the solubility from Kspand vice versa. Consider the following equilibrium be...

    Learning Goal: To learn how to calculate the solubility from Kspand vice versa. Consider the following equilibrium between a solid salt and its dissolved form (ions) in a saturated solution: CaF2(s)⇌Ca2+(aq)+2F−(aq) At equilibrium, the ion concentrations remain constant because the rate of dissolution of solid CaF2 equals the rate of the ion crystallization. The equilibrium constant for the dissolution reaction is Ksp=[Ca2+][F−]2 Ksp is called the solubility product and can be determined experimentally by measuring thesolubility, which is the amount...

  • help with questions please TA'[B Write the expression for the equilibrium constant for the following reactions:...

    help with questions please TA'[B Write the expression for the equilibrium constant for the following reactions: N204 (g) 2NO2 (g) N2 (9) + 3H2 (g) = 2NH3 (9) Solids are not included in the expression since the concentrations do not change. After you write the expression, explain why the solid concentrations do not change. MgCO3(s) = MgO(s) + CO2(g) Solvents are not included in the expression since the concentrations do not change. After you write the expression, explain why the...

  • Help please! Show work cs 6. The equilibrium constant for the reaction in question 2c is...

    Help please! Show work cs 6. The equilibrium constant for the reaction in question 2c is K. = 721 M . (a) Assuming this reaction is at equilibrium, calculate [I] when [12] = [1:1 = 0.0010 M. (b) Assuming this reaction is at equilibrium, find [I:-) when [12] = 0.0025 M and [1] = 0.010 M. (c) Assuming this reaction is at equilibrium, find [12] when [13"] = 0.00030 M and [1'] = 0.10 M. (d) Before the reaction reaches...

  • show and explain work please 6. Calculate the equilibrium constant at 25°C for the following reaction:...

    show and explain work please 6. Calculate the equilibrium constant at 25°C for the following reaction: Cd(s) + Sn** (aq) → Cd²+ (aq) + Sn(s) K = 6.3 x 108

  • please help answer QUESTION 2 Calculate the value of the equilibrium constant for the following reaction...

    please help answer QUESTION 2 Calculate the value of the equilibrium constant for the following reaction at the indicated conditions: H20H30 (0) OcT(aq) + + HOCI 0.004 M pH 1.044 OCT-0.00455 M (express the answer to 5 decimal places) QUESTION 3 Calculate the equilibrium constant for the following: PbClz (s)PbCl2 (aq) Use the equilibrium constants in appendix 10 and 12. (don't use other sources!!!) NOTE: the Ksp for PbCl2 is incorrect in the textbook tables, but the value for pKso...

  • please help with these two questions QUESTION 2 Consider the following reaction and its equilibrium constant:...

    please help with these two questions QUESTION 2 Consider the following reaction and its equilibrium constant: SO2(g) + NO 2(0) SO 3(g) + NO(g) K c = 0.33 A reaction mixture contains 0.41 M SO 2, 0.13 M NO 2.0.11 M SO 3 and 0.13 M NO. Which of the following statements is TRUE concerning this system? The reaction quotient will decrease The reaction will shift in the direction of reactants. The reaction will shift in the direction of products,...

  • help please? this was the only other information given REPORT SHEET Determination of the Solubility-Product Constant...

    help please? this was the only other information given REPORT SHEET Determination of the Solubility-Product Constant for a Sparingly Soluble Salt EXPERIMENT 8 A. Preparation of a Calibration Curve Initial (Cro121 0.0024 M Absorbance 5 mL Volume of 0.0024 M K Cro Total volume 1. I mL 100 mL 2. 100ML 3. 10 mL 100ml 4. 15 mL 100 ML Molar extinction coefficient for [CrO2) [Cro,2) 2.4x100M 12x1044 2.4810M 3.6810M 0.04) 2037.37 0.85 1.13 2. 3. Average molar extinction coefficient...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT