K=exp(-21.71*103J.mol-1/8.314Jmol-1K-1*298K)
K= exp(-8.7626111371)
K=0.0001564755
What is the value of K for this aqueous reaction at 298 K? A+B F C +D AG° = 21.71 kJ/mol K =
What is the value of K for this aqueous reaction at 298 K? A+B=C+D AG° = 29.82 kJ/mol K=
What is the value of K for this aqueous reaction at 298 K? A+B= C+D AG = 21.79 kJ/mol -6601
What is the value of K for this aqueous reaction at 298 K? A+B= C+D AG° = 15.08 kJ/mol K = 1.661 x10-6
What is the value of K for this aqueous reaction at 298 K? A+B = C+D AG° = 19.57 kJ/mol K =
What is the value of K for this aqueous reaction at 298 K? A + B F C + D AG° = 15.82 kJ/mol KE 0
What is the value of ?K for this aqueous reaction at 298 K? A+B↽−−⇀C+D Δ?°=26.52 kJ/mol
What is the value of k for this aqueous reaction at 298 K? A+B<——>C+D. DeltaG=15.23 kJ/mol
What is the value of ? for this aqueous reaction at 298 K? A+B↽−−⇀C+DΔ?°=14.14 kJ/mol A + B ↽ − − ⇀ C + D Δ G ° = 14.14 kJ / mol ?= K =
What is the value of K for this aqueous reaction at 298 K? A+B F C +D AG° = 20.93 kJ/mol K = At 25 °C, the equilibrium partial pressures for the reaction 3 A(g) + 2 B(g) = C(g) + 2D(g) were found to be Pa = 4.86 atm, PB = 5.54 atm, Pc = 4.91 atm, and Pb = 5.82 atm. What is the standard change in Gibbs free energy of this reaction at 25 °C? AGеxn =...
What is the value of ? for this aqueous reaction at 298 K? A+B↽−−⇀C+DΔ?°=29.94 kJ/mol A + B ↽ − − ⇀ C + D Δ G ° = 29.94 kJ / mol