Molar mass of NH4Cl,
MM = 1*MM(N) + 4*MM(H) + 1*MM(Cl)
= 1*14.01 + 4*1.008 + 1*35.45
= 53.492 g/mol
mass(NH4Cl)= 52.7 g
use:
number of mol of NH4Cl,
n = mass of NH4Cl/molar mass of NH4Cl
=(52.7 g)/(53.49 g/mol)
= 0.9852 mol
volume , V = 5.352*10^2 mL
= 0.5353 L
use:
Molarity,
M = number of mol / volume in L
= 0.9852/0.5353
= 1.841 M
Answer: 1.84 M
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