Question

Grossmont College Phy US aday Fundamentals of Physics, 10 Agent Grade RON Downloadable Textbook FULL SCREEN PRINTER VERSION MESSAGE HY INSTRUCTOR Chapter on. Problem 020 m 13 from rest on a frictions incline of ange 25 Below the blocks spring that can be compressed 13 cm by a force of 230 N. The block enty when it comesses the song by 5.9m (a) How to does the block move down the inne omrest post to the init() What the speed of the block as it touches the spring? (6) Number By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor, Question Attempts: 0 of 10 used SAVE FOR LATER SUBMIT ANSWER Earn Maximum Points available only if you answer this question correctly in four attempts or less y 10.2000-2019hn Wiley Sons Inc. All Rights Reserved. A Division of John Wil s on Inc Version 4.2

Answer 1

given
m = 13 kg
theta = 26 degrees
spring constant, k = 230/0.013

= 17692 N/m
a) Let L is the total distance traveled by the block along the inclined surface before coming to momentarily stop.

increase in elastic potential energy stored in the spring = decrease in gravitational potential energy

(1/2)*k*x^2 = m*g*L*sin(theta)

==> L = (1/2)*k*x^2/(m*g*sin(theta))

= (1/2)*17692*0.059^2/(13*9.8*sin(26))

= 0.551 m (or) 55.1 cm <<<<<<------Answer

b) let v is the speed of the block just before tocuhing the spring.

(1/2)*m*v^2 = m*g*(L - x)*sin(theta(

v = sqrt(2*g*(l - x)*sin(theta))

= sqrt(2*9.8*(0.551 - 0.059)*sin(26) )

= 2.06 m/s <<<<<<------Answer