Question

1. Precipitation reaction given two reactants containing appropriate cations and anions, predict the product solid (precipitate) and the soluble second product. Write a balanced molecular equation, a complete ion ic equation, and/or a net ionic equation for the reaction. a.) MgC12 _NaOH b.) Pb(NO3)2_K2SO4 2. Mg 2 HCI MgCl2 H2. If a chemist uses 20 g Mg and excess HCI, what mass of MgC12 product would form? 3. Mg + 2 HCI MgC12 H2. If a chemist uses 20 g Mg and excess HCI, what mass of HCI will react? 4. Mg+2HCI-MgC12 +H2. If a chemist uses 20g Mg and 20g HCl, what is the limiting reactant? What mass of the excess reactant is left over when the reaction is complete? 5. Mg+ 2 HCI MgCl2 H2. If a chemist wants to produce 6.50 g of H2 gas, what mass of Mg reactant should be used? (Assume excess of HCI and perfect 100% yield.) 6.A chemist predicts a theoretical yield of 5.38 g product. The lab manual reports 85% yield is typical for the reaction. What actual yield should the chemist expect from his reaction? 7.A journal article reports an actual yield of 38.23 g and percent yield of 93.2%. What was the theoretical yield? 8. What volume of 12.0 M nitric acid is required to prepare 3.34 L of 0.100 M nitric acid?

Answer 1

balanced Aatin ca) (ey) (Ay (SJ Cotplete Ton equhon (ay) ah) Can) det 1oc e Uation (S) Cy) Vet Ton equtiy ( y SJ

banced eim PL Soy Ko3 (SJ (asy) ay Conpiete Iani equation: SoH (ay (S) (ay (asy)(ay Jet Ionic euation: Soy (SJ +Sou (av Psto Sa a) Pbsay (S et Ioni ekf PLt as)

24.3 9 ot ng produte produ ceg a5.2 gh of fgu १५-3 7.35 9h at-35 gr ct t9

3) HytHc t Mole (4.39ns) Rets k noles of c (72 s) 60.08 Reucts wik b0 gh t Huany ry

toles ot yweigkt of ty -0.883 Moles 2 n.telez Foles dH: weyht 3.5 0-4nolez (oy gY9 hinuls Het la les JunLer Te liritiny Reagent Tuso Reactang atony he t holey tus Hel Require Irove hg (24-3 CBgnsy Renvires 2 Elee ot ty (gp ns) 0.5 noleg k HeA1n SLA X t43 actial Reguiel hy CY cegs P= fy Used in Reaction (.6५5 % 13.3 7/7 dt t in cxes

ve hokity t H (betore Ditution)= 18H ViVolute t re okityot Hz o1 (atter oilutian) V3Volute o eleg ( i l0te- 3-24 it Sokuton 3,34o hL Llak is Dilutecl Solutia f५ : ० Ih Vi 0.1X 3340 L z .833 hL vistuteel si aer, hen rokwty i Solutin 0-17 Resultount ahoun Jater addedz 3340 HL- 27-833 h 33 r otter ades dote: 8/8