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eBook Suppose that Motorola uses the normal distribution to determine the probability of defects and the number of defects in
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Answer #1

a)

probability = 1-P(9.85<X<10.15) = 1-P(-0.5<Z<0.5)= 1-(0.6915-0.3085)= 0.6170

b)

probability = 1-P(9.85<X<10.15) = 1-P(-1.5<Z<1.5)= 1-(0.9332-0.0668)= 0.1336
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