The specific heat of iron is 0.450 J/g°C
Ans 1 :
Heat = mass x specific heat x change in temperature
here mass of coffee :
= density x volume
= 250 mL x 1 g/mL = 250 g
specific heat = 4.18 J/goC
so putting values :
heat = 250 g x 4.18 J/goC x (95.6oC - 20.5oC)
= 78479.5 J
so 78479.5 Joules of energy is required
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