What do we conclude about xj if we can reject H0: βj = 0 in favor of Ha: βj ≠ 0 by setting (a) α equal to .05? (b...
| What do we conclude about xj if we can reject H0: βj = 0 in favor of Ha: βj ≠ 0 by setting |
| (a) α equal to .05? |
| (b) α equal to .01? |
xj significantly related to y with (a) (Click to select)nonevery strongstrongsomeextremely strong or (b) (Click to select)somevery strongextremely strongstrongnone evidence.
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What do we conclude about xj if we can reject H0: βj = 0 in favor of Ha: βj ≠ 0 by setting (a) α equal to .05? (b...
Use the Excel output in the below table to do (1) through (6) for each ofβ0,...
Use the Excel output in the below table to do (1) through (6) for each ofβ0, β1, β2, and β3. y = β0 + β1x1 + β2x2 + β3x3 + ε df = n – (k + 1) = 16 – (3 + 1) = 12 Excel output for the hospital labor needs case (sample size: n = 16) Coefficients Standard Error t Stat p-value Lower 95% Upper 95% Intercept 1946.8020 504.1819 3.8613 0.0023 848.2840 3045.3201 XRay (x1) 0.0386...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d⎯⎯ =4.6d¯ =4.6 of and a sample standard deviation of sd = 7.6. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ , ] ;...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed...
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d¯ =5.0d¯ =5.0 of and a sample standard deviation of sd = 7.8. (a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.) Confidence interval = [ , ] ;...
Consider the following hypothesis test. H0: μ1 − μ2 = 0 Ha: μ1 − μ2 ≠...
Consider the following hypothesis test. H0: μ1 − μ2 = 0 Ha: μ1 − μ2 ≠ 0 The following results are for two independent samples taken from the two populations. Sample 1 Sample 2 n1 = 80 n2 = 70 x1 = 104 x2 = 106 σ1 = 8.4 σ2 = 7.2 (a) What is the value of the test statistic? (Round your answer to two decimal places.) (b) What is the p-value? (Round your answer to four decimal places.)...
Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at...
Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 70 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. (a) Letting µ represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis H0 and the alternative hypothesis Ha needed if we wish to...
Consider the following competing hypotheses: H0: ρxy ≥ 0 HA: ρxy < 0 The sample consists...
Consider the following competing hypotheses: H0: ρxy ≥ 0 HA: ρxy < 0 The sample consists of 30 observations and the sample correlation coefficient is –0.46. Use Table 2. a. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic b. Approximate the p-value. 0.005 < p-value < 0.01 p-value < 0.005 0.01 < p-value <...
Consider the following hypothesis test: H0 : u = 100 Ha : u not equal to...
Consider the following hypothesis test: H0 : u = 100 Ha : u not equal to 100 A sample of 80 is used. Identify the -value and state your conclusion for each of the following sample results. Use a=0.05 . Round the value of the test statistic to three decimal places. If required enter negative values as negative numbers. a. x bar = 115 and s = 12 t-value p-value - Select your answer -lower than .01, between .01 and...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor...
In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 142 use humor, while a random sample of 500 television ads in the United States reveals that 124 use humor. (a) Set up the null...
The manufacturer of the ColorSmart-5000 television set claims that 95 percent of its sets last at...
The manufacturer of the ColorSmart-5000 television set claims that 95 percent of its sets last at least five years without needing a single repair. In order to test this claim, a consumer group randomly selects 396 consumers who have owned a ColorSmart-5000 television set for five years. Of these 396 consumers, 311 say that their ColorSmart-5000 television sets did not need repair, while 85 say that their ColorSmart-5000 television sets did need at least one repair. (a) Letting p be...
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