7) option D is correct
Explanation: -COCH3 is a strong electron withdrawing group which withdraws electron density and directs the incoming electrophile to meta position.
8) option E is correct
Explanation: alkyl group on benzene ring is an electron donating group and directs the incoming electrophile to para position.
What product is formed when acetophenone is reacted with fuming sulfuric acid? SOZH SOH I II IV A. II B. IV C. I D....
please help What product is formed when acetophenone is reacted with nitric acid and sulfuric acid? 7. OCH3 ОсH sOH NO2 NO2 NO2 I П ш IV А. П В. IV С. I D. III E. None What product is formed when isopropylbenzene is reacted with 2-chloro-3-methy I butane and aluminum 8. trichloride? AIC of IIl А. IV В. C. I D. V E. II F. None ast t
7. What product is formed when acetophenone is reacted with nitric acid and sur OCH OCH3 SO3H NO, NO2 ги шу A. II B. IV C. I D. III E. None 8. What product is formed when isopropylbenzene is reacted with 2-chloro-3-methylbutane and aluminum trichloride? I II IV V B. III C. I D. V E. II F. None
hat product is formed when isopropylbenzene is reacted with 2-chloro-3-methylbutane and aluminum trichloride? AICI III IV 3 A. IV B. II I - D. V E. III F. None Identify which ammonium ion has the lower pka. Use aromaticity concepts to explain your answer. 1-20
3. identify the product formed when 3 phenyl 3 oxopropanol is reacted with ethylene diamine. 4. select the expected product from the reaction shown 5.select methods to prepare n-butylqmine without complications. are strong because of the lone pale on pitrogen is delocalized into the ring 3. Identify the product formed when 3-phenyl-3-oxopropanal is react ut formed when 3-phenyl-3-oxopronnal is reacted with the ethylene diamine. NH NH H,00 NH2 C. W E. None 4. Select the expected product from the reaction...
Predict the product for the fallowing reaction. A) I B) II C) III D) IV E) none of these Predict the major product for the following reaction. A) I D) II C) III D) IV E) none of these
11. Identify the product(s) of the following reaction. A. I B. II C. III D. IV E. V Gom Do is a From co be on) porno porno olyan 12. What is the final product obtained when toluene is subjected to the following reaction sequence? i) Clz (large excess), heat, hv; ii) OH-/H20, heat; iii) H30+ A. I OH B. II OH COH C. III U OH D. IV E. V I II Hol YCC, III HOCCI3 C/ стон с...
86. What is the formula for lead (IV) sulfide? B) PbS A) PbS C) Pb S D) Pb,S E) Pb,S 87. What is the name of H3PO4? A) hydrochloric acid C) sulfuric acid D) phosphoric acid E) none of these B) nitric acid 88. What is the name of Co,O,? A) dicobalt trioxide cobalt (II) oxide D) cobalt (III) oxide B) cobalt trioxide C) E) dicobalt (I) trioxide 89. What is the name of H2SO4 A) hydrosulfuric acid C) sulfuric...
F2019-Chem 232-Org II Multiple Selection section (3 pts/ each) 1. Select the product formed from adding Lithium aluminum hydride to 6-hydroxy-3-p- cyanophenylheptan-2-one. (3 pts) ОН Oh oh 32 I A. B. C. D. IV E. None 2. Select the correct ranking of base strength for the amines shown (from weakest to strongest), NH2 NH2 1 III IV A. Klll<ll<IV B. IKIIVI C. kli<ll<IV D. IV<ll<llll All are strong because the halogens are electronegative dently the product formed when 3-phenyl-3-oxopropanal is...
61. What product is finally formed when the initial compound formed from cyclohexanone and pyrrolidine is mixed with allyl chloride and that product is heated and then hydrolyzed? HO ora III A) I B) II C) III D) IV E) V 59. Which reagent would best serve as the basis for a simple chemical test to distinguish between CH3 ? CH3 and M A) NaOI (12 in NaOH) B) Bry/CCL C) CrO3/H2SO4 D) NaHCO3/H20 E) Ag(NH3)2+ 60. What would be...
Hасо. NO2 но,5 NO I1 d) I and II in roughly equal amounts. c) II b) II a) e) I and IlII in roughly equal amounts. 6. What would be the major product(s) of the following reaction? H-SO NO2 но,5. soH NO2 HO3S NO2 NO2 NO2 IV III II I e) Equal amounts of II and IV. d) Equal amounts of I and IV. c) III b) II a)1 is subjected to the action of the following reagents in the...