Question

For the following circuit, compute Vx, Vy, Vxy, Ixy, I norton, and Rthevenin.

EET 118- LABORATORY EXPERIMENT #1 Table #4 Original Circuit-Figure #2 Thevenin Equivalent Circuit Resistance Values Nom Meas 10k R1 R %E RI A0h d 0.17 R2 310k R4 20k R2 Vs RL w 10k x R3 20 V R4 20h 19.9950.25 R5 10k 990.2% RL 16 9.98 R3 50k RS 310k Step#4 Step # 8 Theoretical Step #3 Measured Step #7 Theoretical Step # 6 Measured Stép #9 Parameter &#5 Values Values Values Values Measured Values 6.316.151 5.$37V 4473 2.5 V 10 2.6lv 0.253 0.163mf 0,6 C.46 Vx Vy Vxy Ixy VThevenin's 0.MBad INorton's 16.65 RThevenin's Computations for Table # 4 are to be recorded in an organized format in the Laboratory Report. Note: measured resistance values are used in all computations on a separate pag +5

Answer 1

ok analyses Noda 20k Node Volagu- Vi,Vx&V $50k RIDK kCL at Node Vi5 Vi-Vx + loK 1DK 2(vi-20)2(v\-Vx) +V,-Vy 5-2V-V - 40 KCL at Node V^- -V Vx-VW lok 50K o k 5(V- 5V^-VyJ +Vk 50k 5V 1V -5V 0 KCL at Node Vr VY-Vx ok lok VY-VI 2(VY.V*) 42V 20k -V2V2 +5¥y =0 Solve we qet Vi= 12.5 g.333 V V VY=5.838 v

5.833 V Vxy= Vx-W =8333-5-&33 = 2.5 V Ixy/2-5/1pxi = o.26 x A Inost ) Ise Ishntckt)'r oK RI Mesh amalyti ROK Mesh Cument?t kVL in mesb i- -0) 20 KVL in mesh i,i + - 50x1o3 i, +6oxto Solve e D, i30.667X13 A KeL at node Y; Ise O.4x Lo3 N

R shoxt ckt 1OK 310K lok Raa0k 1ok O Y X T50k lok tokx5ok Toklokt 50k7.143 K »_ M Nokxiok i428 kr oktiokt5o ok50K 7기43 K. Ioktlokt50k 글20k) 429 K,2oK are a Serie M. X 7-143K -143K al.419 K 7.143K4 lok- 17-143 R 21-421k X. 7-142 k 743 K 21.419kk 17.143 kA partly a in (ai.4241)(17.143x1 1.429 a10 17.14sx1f AN 142 K 9.524k = 7-143 k+9 524 K = 16 667 k 16.667 K -