question 11)
pH = pKa + log ( A- / HA)
HA = NaH2PO4
A- = Na2HPO4
pH = pKa + log ( Na2HPO4 / NaH2PO4)
pKa of NaH2PO4 = 7.2
pH = 7
7 = 7.2 + log ( Na2HPO4 / NaH2PO4)
log ( Na2HPO4 / NaH2PO4) = 7 - 7.2
log ( Na2HPO4 / NaH2PO4) = - 0.2
Na2HPO4 / NaH2PO4 = 10^(-0.2)
Na2HPO4 / NaH2PO4 = 0.631
NaH2PO4 / Na2HPO4 = 1 / 0.631
NaH2PO4 / Na2HPO4 = 1.5
so the ratio is 1.5 NaH2PO4 / 1.0 Na2HPO4
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