Question

A solution of benzene (C6H6) and toluene (C7H8) is 29.0 % benzene by mass. At 25∘C the vapor pressures of pure benzene and pure toluene are 94.2 and 28.4 torr, respectively. Part A Assuming ideal behavior, calculate the vapor pressure of benzene in the mixture. Express the pressure to three significant figures and include the appropriate units. Part B Assuming ideal behavior, calculate the vapor pressure of toluene in the mixture. Express the pressure to three significant figures and include the appropriate units. Part B Assuming ideal behavior, calculate the vapor pressure of toluene in the mixture. Express the pressure to three significant figures and include the appropriate units.

Answer 1

solution of the soluhion= l00g amount of benzene (CsH) let the masS hence = l00 x29 = 2 00 mole ofbenzene mass 29 mole molar mass 78 of toluene =(00-24)g = " mass 71 mole mole of toluene 92 Raoult's law Pohuene Xtoluene + total vapour pressuse of solution = Penzene Xgenzene 71 29 18 - 94-2 x t 28.4 x 29 92 71 71 92 29 78 78 ( (44-2x0-325)+(284x0675) toluene bеnzеие 19. 166 30 615 benzene toluene 49-781 toxx total vapour pressunc of salutiou) vapour pressune of pune benzene in solu hiou (Peenzene) Hence =30.6 tox8 Vapour pressune of toluene (Proluene)= 192 torr Ans