Problem #4: At 29.6 °C, pure water has a vapor pressure of 31.1 torr. A solution...

Question

Question

Answer 1

Answer #1

P solution = X solvent * P⁰solvent

28.6 = X solvent *31.1

X solvent = 28.6/31.1 = 0.92

no of moles of water(solvent) = W/G.M.Wt

= 350/18 = 19.44moles

mole fraction of solvent = no of moles of solvent/ total no of moles

0.92 = 19.44/19.44 + y

0.92(19.44+y) = 19.44

y = 1.69moles

molar mass of y = 86.8/1.69 = 51.4g/mole

Answer 2

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