Question

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Measured Force Constant, k (N/m): 5.29 (20 points) Mass, m (kg)_0.100 kg tittettststtst Time (s) 208 2.94 3.844.12 5.60 6.48 1.36 8.249.14 Period (s) .86.9 -88 -88.88.88.88.9 Calculate the experimental values for the period of oscillation between each consecutive time value, then use those values to calculate the experimental average period value. (10 points) Average Period, Tavg (s): -88 Physical Quantity Crest (m) Trough (m) Amplitude (m) Position Wave 501 .348 0.79 Velocity Wave I-0.57 0.565 Acceleration Wave - 4 3.46 13.3 Calculate the amplitude of each wave by using the following equation. (10 points) A crest - trough 2

Answer 1

1) Period = 2π√(m/k)

= 2*3.14*√(0.100/5.29)

=0.863439 s

2) %error = (theoretical period -expirimental period) *100

=0.863439-0.88)*100

=0.01656*100

=1.656%

3) The kinetic energy of a simple harmonic system is maximum at the mean position or at equilibrium position. That is, velocity is maximum when the mass it at its equilibrium position.

4) the kinetic energy or the velocity of a simple harmonic system is minimum at the extreme positions. Thus the mass is at the extreme position relative to equilibrium position during zero or minimum velocity