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A solution of 2.68mM in a 2.50 cm cell has a transmission of 0.156. What would...

A solution of 2.68mM in a 2.50 cm cell has a transmission of 0.156. What would the concentration be if instead the transmission was 3 fold greater and the path length halved.

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Answer #1

solution: - log (T) = Elc where Te Transmittance - la length or path length . c = concentration = Molay Absorption coefficient Given: -

2 c, a и 2 : 60 х 2 Sь lo9 (6 ч 68 ) О. ІSB) 1 1 1 Г. 36 р, чо 7 2. 19 мм

Hence, the final concentration after change is = 2.19 mM

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