Question

refer to picture.

A boy pulls his younger sister on a toboggan by a rope that makes an angle of 37.0° with the horizontal, as shown. The boy maintains a tension of 25.0 N in the rope and walks, on level ground, at a constant speed of 1.10 m/s. The combined mass of the girl and the toboggan is 30.0 kg. Determine a. the normal force exerted on the toboggan by the ground. the coefficient of kinetic friction between the toboggan and the ground. the work done by the tension on the girl-toboggan system in one minute. 1.1 m/ 370

Answer 1

a Flinsto ra) v 1870 --> Flossyo . .: Ping? N= Narmal force on girl by toboggan. Is - Normal farie on toboggan by the ground Maria Mass of girl .... mz Mass of loboggan. Apply Newton's Second law .. N4 Exingzoz (Hemegen N'+ FSin3yo anting N"; F Sin3yo 2 (Mg + m) g. Ne 30x9.8 -- 25 X 0.6 (N = 27.9 Newton) «اله : ,

b)

Line, there is no acceleration the Horizontal .. ension component equals to the kinetic friction farce... : Flex37° = MN!! (25x0.798 = Mal 1.279 i ley = 0.0715) ; () Work done by the lension on.gial toboggan system a (W = Floos 37° 5) . . Sa distance covered in 1 minuli sa u.t = (1-4 * 601 266 W = 25*0.798 866 (W = 1316.7. Soule)