A) it forms acidic buffer,
pH = pKa + log([NO2-/HNO2])
= 3.35+log(0.21/0.36)
= 3.11
B) it basic buffer,
pOH = pKb + log(NH4Cl/NH4OH)
= 4.74+ log(0.45/0.60)
= 4.62
[OH-] = 2.46×10-5 M
pH = 14-4.62
= 9.38
will you show me how to work these? Pietleas to do tof taofou H+NO HAO .2M...
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