Question

I know part A is downwards. But I’m not sure how to solve Part B. Help please!

(10%) Problem 10: Consider the arrangement of point charges in the figure. la qa Otheexpertta.con 9,-+7.50 μC and 9.-9,--7.50 μ q) 50% Part (a) Determine the direction of the force on q (with q > 0) in the figure, given that 9a Straight downward Correct 50% Part (b) Calculate the magnitude of the force on the charge q in newtons, given that the square is 13 cm on a side and q-1.25 C Grade Summary

Answer 1

O gp L=013 m Fd i: Fa go

L = length of side of the square = 0.13 m

r = distance of each corner from the center

distance of each corner from the center is given as

r = L/sqrt(2) = 0.13/sqrt(2) = 0.092 m

q' = magnitude of charge at each corner = 7.5 x 10^-6 C

q = magnitude of charge at center = 1.25 x 10^-6 C

F = magnitude of force on the charge at center by each charge at the corner

magnitude of force on the charge at center by each charge at the corner is given as

F = k q' q /r²

F = (9 x 10⁹) (7.5 x 10^-6)(1.25 x 10^-6)/(0.092)²

F = 9.97 N

so F_a = F_b = F_c = F_d = F = 9.97 N

F_ad = combination of force F_a and F_d = F_a + F_d = 9.97 + 9.97 = 19.94 N

F_bc = combination of force F_b and F_c = F_b + F_c = 9.97 + 9.97 = 19.94 N

magnitude of the net force is given as

F_net = sqrt(F_ad² + F_bc²) = sqrt((19.94)² + (19.94)²) = 28.2 N