Question

Page 12 of 12 BG10.2 Acid-Base Titration s part of a lab exam, your instructor gives you a sample of hydrochloric acid and asks you to ermine its concentration using the procedure in this lab. You make up a solution of sodium hydroxide droxide by dissolving 2.0 g of sodium hydroxide pellets in water and diluting it to exactly 500 me. You then titrate your sodium hydroxide solution three times with a hydrochloric acid solution with a molarity of 0.1024 molliter. You measure the volumes of reagents in the table below. Calculate the best estimate of the molarity of the sodium hydroxide solution and the relative deviation of the results. Trial Molarity of Base, Deviation from mL of acid mL of Base MoVL Average 25.89 23.23 27.43 24.93 24.55 21.83 Avg Rel. Avg. Dev. 3. You now titrate the unknown hydrochloric acid solution with your sodium hydroxide solution which you standardized above. Use the molarity for the sodium hydroxide solution that you calculated in 2. Above to calculate the molarity of the acid solution. The volumes of reagents are shown in the table below. What is the best estimate of the concentration of the hydrochloric acid solution? What is the relative average deviation of your measurement of the hydrochloric acid solution? Molarity of Acid, Trial mL of Base Deviation from mL of acid Mol/L Average 24.73 29.86 27.21 33.20 22.44 26.69 Avg Rel. Avg. Dev.

Answer 1

2. Solution is - al Molarity of Buse Moly Base Acid el introm Av. Trial 1. 2. 3. ml of more molarity Derivation from Aro ] 25,89 23,23 10.114 | 0.086 27.43 24.93 0.113 0.087 24.55121.83 10.115 0.085 Av. 0.119 Rel Av. = 0.086 Dev. Molasity of Base (Maroon) ! - wt of Naoh taken = 28 Volume of Naoh solution. Made = 250 ml M Nash = wt, 1000 Mnaon= ? Mw* Vemo Mnaon= 2 1000 to 200 4000 Mnaon= .2M too trial-1 Maria Acid = Mbase V Base (Both have samevalance y [ ( Macid = 1024 factor Given) ·1024 x 25,892 23.23% Mease Mease= MNAOH = 0.114 for trial-2 Appling the above formula .102427.43= Measex24.93 Mnaoh .113 fortrial-3 1024 x 24,55 € Makowy x 21.83 I'M Naol = 0115