Question

In the figure, projectile particle 1 is an alpha particle and target particle 2 is an oxygen nucleus. The alpha particle is scattered at angle 01 = 64.9° and the oxygen nucleus recoils with speed 1.30 x 105 m/s and at angle 02 = 51.0°. In atomic mass units, the mass of the alpha particle is 4.00 u and the mass of the oxygen nucleus is 16.0 u. What are the (a) final and (b) initial speeds of the alpha particle?

Answer 1

Solutions we use the conservation of momentum M . V2,4 los 62 X vit Cose initial & y Vis sing, o final momentum along then ani's should be equal hence along na anis mivi = M2 V 24 (os O₂ + mi vi Love, 4.90 V 16x130x15 cos so & 4. Vit los 6419 4 Vi= 113 8106 + 1.697. Vit alongyanis o mal af sino mi visina

2 m₂ Vast sing O2 = m, vit sing, 2 168 1.3 x 105 sinsl = 4X Vit Sin 6419 Vit = 1.68105 -3.62 Vid = 4.4.2 4104 mis ! putting in 4 Vid = 1.34106 +1.697x 4 . 428104 Tii= 3.43410 m/s]