Question

KHomework 1 Problem 22.41 12 a 17> Review Lxpress your answer with the appropdate unts F-1 Value Unils Submit ▼PartB Figure 15 nC 50 nc 3.0 cn Picvide Feedback Naxt > CT

Answer 1

Your image quality (of the question) is not too good i.e. i can't understand it is a = 2.6 cm or a = 26 cm . So, i am considering a = 2.6 cm. If i have taken some wrong values please replace it by whatever value you want and follow the same procedure.

Part A :

The diagram for the forces acting on -10 nC charge is shown below :

Here, AB = 3.0 cm = 3 x 10^-2 m , BO = 2.6 cm = 2.6 x 10^-2 m

So,   

F₁is force acting on -10 nC charge by -15 nC charge.

And F₂ is force acting on -10 nC charge by +5.0 nC charge.

The magnitude of electrostatic force between two charges (q and Q) separated by a distance r is given by

Where,

By using this equation we can calculate the F₁ and F₂ as :

  

15 × 10-9 × 10 × 10-9 402 AO2 10-9 , 1-9 × 109 ×

And

  

  

50.0 × 10-9 (2.6 × 10-2)2

7.396 × 10-5

We can calculate the angle as

So, we can write the forces in vector notation as

or,

or,

And   

So net force on charge -10 nC is

  

F=F1 + F2

So, the magnitude of net force is

  

v/6562.05 × 10-10-81.00 × 10-5

Part B :

Direction of net force F can be calculated as

"(ALT )--36.95° ~-37

Where, is angle made by net force with x - axis .

For any doubt please comment and please give an up vote. Thank you.