According to the Markownikov's rule, in addition reaction of a hydrogen halide to an alkene/alkyne, the Hydrogen atom will get bonded to the carbon atom (forming the double/triple bond) containing larger number of hydrogen atoms and the halogen atom will be bonded to the other carbon of the double/triple bond.
So in given reaction, as there is excess HI, so first it will add to the double bond to give the product as shown.
Further more of HI will
add to give the final product as shown.
So we can see that the hydrogen gets added to the terminal C as it had 1 Hydrogen to begin with and the halogen (I) gets added to the second carbon (part of the triple bond), this happens till we get a saturated compound shown as the final product where both I are attached to the second carbon. So option C is the correct answer.
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