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You may want to reference (Pages 347 - 348) Section 11.8 while completing this problem. When heated to 350 °C at 0.950 atm, a how many grams of NH4NO3 are needed to produce 18.0 L?
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Answer #1

T= 350°C = 623K P=0.950 atm v=18.04 M= 80.043 g/mol W=? Pu= u RT 0.950 X 10.0= X0.0821 X 623 80.043 w=26.8 g 26-8 grams of NH

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