Homework Answers
The reaction proceeds towards reactants , because there is
no O2 in the begining.
N2(g) + O2(g) <====> 2NO(g)
initial 5.09 mol - 30.33/28 = 1.088 mol
change +x +x -2x
equil 5.09+x x 1.088-2x
total no of moles of gaseous mixture at equilibrium(n) =
1.088-2x+5.09+x+x
= 6.178 mol
at equilibrium,
as Dn rxn = 0
Kp = Kn = nNO^2/nN2*nO2
0.101 = (1.088-2x)^2/((5.09+x)*x)
x = 0.331
pNO = nNO/nTotal*pTotal
= ((1.088-2*0.331)/6.178)*3.14
= 0.216 atm
pO2 = (0.331/6.178)*3.14
= 0.168 atm
pN2 = ((5.09+0.331)/6.178)*3.14
= 2.76 atm
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