Question

Let f,g be continuous functions on [a,b] with f(x) 0 for all rE a, b

(a) show that there are a, 1 such that

( f(xgf(x) < g[x2}f{x))

(b) using (a) prove that there is a \varepsilon strictly between x1 and x2 such that

f(r)g()da g(e) f(x)da

f(x) 0
rE a, b
a, 1
( f(xgf(x)
0 0
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Answer #1

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